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Probability Distributions — Book-Back Answer Key (Exercise 11.6)

Probability Distributions — Book-Back Answer Key (Exercise 11.6)

All twenty multiple-choice answers below were re-worked independently. Each one agreed with the official key, so no corrections were required.

QAnswerWhy
1(2) mean exists, variance does not\(E(X)=\int_1^\infty \tfrac{2}{x^2}\,dx=2\) is finite, but \(E(X^2)=\int_1^\infty \tfrac{2}{x}\,dx\) diverges.
2(4) \(\tfrac{l}{2},\ \tfrac{l^2}{12}\)Uniform on \((0,l)\): \(\mu=\tfrac{l}{2}\), \(E(X^2)=\tfrac{l^2}{3}\), so \(\sigma^2=\tfrac{l^2}{3}-\tfrac{l^2}{4}=\tfrac{l^2}{12}\).
3(2) \(-\tfrac{19}{6}\)\(E=\tfrac{1}{6}(36)-\tfrac{1}{6}(1+4+9+16+25)=6-\tfrac{55}{6}=-\tfrac{19}{6}\).
4(4) \(4\)Sum \(=7\) from \((3,4),(4,3),(5,2),(6,1)\) — four pairs.
5(4) \(2\)\(\sigma=\sqrt{npq}=\sqrt{25(0.8)(0.2)}=\sqrt{4}=2\).
6(2) \(2i-n\)With \(i\) heads, the difference is \(i-(n-i)=2i-n\) for \(i=0,\dots,n\).
7(4) \(16\) and \(24\)A uniform density needs \(b-a=12\); here \(24-16=8\neq 12\).
8(3) \(40.75,\ 40\)Size-biased \(E(X)=\tfrac{42^2+36^2+34^2+48^2}{160}=40.75\); uniform \(E(Y)=\tfrac{160}{4}=40\).
9(2) \(\tfrac{2}{13}\)With replacement, \(E(X)=2\cdot\tfrac{1}{13}=\tfrac{2}{13}\) by linearity.
10(1) \(\tfrac{11}{243}\)\(B(5,\tfrac13)\): \(P(X\ge4)=\tfrac{10}{243}+\tfrac{1}{243}=\tfrac{11}{243}\).
11(4) \(\tfrac{1}{81}\)\(E=3\operatorname{Var}\Rightarrow q=\tfrac13\); with \(n=4\), \(P(X=0)=\left(\tfrac13\right)^4=\tfrac{1}{81}\).
12(4) \(\binom{10}{5}\left(\tfrac35\right)^5\left(\tfrac25\right)^5\)\(np=6,\ npq=2.4\Rightarrow q=\tfrac25,\ p=\tfrac35,\ n=10\).
13(1) \(1\) and \(-1\)\(F(\infty)=a=1\), \(F(0)=a+b=0\Rightarrow b=-1\), giving \(1-e^{-x}\).
14(2) \(2\)\(q=\tfrac{\operatorname{Var}}{\text{mean}}=\tfrac12\); \(np=8\!\left(\tfrac12\right)=4=2k\Rightarrow k=2\).
15(1) I and IIIBulb lifetime and call duration are measured (continuous); a count is discrete.
16(1) \(1\)\(\sum_{x\ge1} a\left(\tfrac12\right)^x=a\cdot 1=1\Rightarrow a=1\).
17(4) \(\tfrac{2}{3}\)\(15k=1\Rightarrow k=\tfrac{1}{15}\); \(E(X)=10k=\tfrac{10}{15}=\tfrac23\).
18(4) \(0.96\)\(\operatorname{Var}(X)=pq=0.24\); \(\operatorname{Var}(2X-3)=4(0.24)=0.96\).
19(2) \(0.25\)\(9p^2=q^2\Rightarrow 3p=1-p\Rightarrow p=\tfrac14\).
20(1) \(\tfrac{57}{8000}\)\(B(3,\tfrac1{20})\): \(P(X=2)=3\left(\tfrac1{20}\right)^2\left(\tfrac{19}{20}\right)=\tfrac{57}{8000}\).
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