Nuclear Physics - Formula Sheet
Core Equations of Nuclear Physics
These key mathematical models and conversion constants govern nuclear reactions and radiation safety:
1. Radioactive Displacement: Alpha Decay
\[_Z\text{X}^A \longrightarrow _{Z-2}\text{Y}^{A-4} + _2\text{He}^4\]
- _Z\text{X}^A: Parent radioactive nucleus with atomic number \(Z\) and mass number \(A\)
- _{Z-2}\text{Y}^{A-4}: Stable or unstable daughter nucleus with atomic number decreased by 2 and mass number decreased by 4
- _2\text{He}^4: Alpha particle (helium nucleus) emitted during the disintegration
2. Radioactive Displacement: Beta Decay
\[_Z\text{X}^A \longrightarrow _{Z+1}\text{Y}^A + _{-1}\text{e}^0\]
- _Z\text{X}^A: Parent radioactive nucleus
- _{Z+1}\text{Y}^A: Daughter nucleus with atomic number increased by 1 and unchanged mass number
- _{-1}\text{e}^0: Beta particle (electron) ejected from the nucleus
3. Radioactive Displacement: Gamma Decay
\[_Z\text{X}^A \longrightarrow _Z\text{X}^A + \gamma\]
- _Z\text{X}^A: Excited parent nucleus returning to a lower energy ground state
- γ (gamma): Emitted high-energy electromagnetic photon, leaving atomic and mass numbers unchanged
4. Einstein's Mass-Energy Equivalence
\[E = mc^2\]
- E: Energy equivalent of the mass defect in Joules (J)
- m: Mass defect (difference between reactant and product masses) in kilograms (kg)
- c: Velocity of light in vacuum, equal to \(3 \times 10^8\text{ m/s}\)
5. Neutron Number Formula
\[N = A - Z\]
- N: Number of neutrons in the nucleus
- A: Mass number (total sum of protons and neutrons)
- Z: Atomic number (total number of protons)
6. Radioactivity Rate Units
\[1\text{ Curie (Ci)} = 3.7 \times 10^{10}\text{ disintegrations per second (Bq)}\]
\[1\text{ Rutherford (Rd)} = 10^6\text{ disintegrations per second (Bq)}\]
\[1\text{ Becquerel (Bq)} = 1\text{ disintegration per second}\]
- Bq: The SI unit of radioactivity
- Ci: The traditional unit of radioactivity, based on the activity of 1g of pure radium
7. Energy Conversions (Electron-Volt to Joule)
\[1\text{ eV} = 1.602 \times 10^{-19}\text{ Joules (J)}\]
\[1\text{ MeV} = 10^6\text{ eV} = 1.602 \times 10^{-13}\text{ J}\]
- eV: Electron-Volt, unit of energy for atomic and nuclear particles
- MeV: Million (or Mega) Electron-Volts
More for this chapter
Book Back Questions12 textbook MCQs · solved
Additional MCQs15 extra MCQs · solved
Practice TestInteractive · instant score
Book Back TestTest yourself on the textbook set
Additional MCQ TestTest yourself on the extra set
Study NotesConcepts & methods
More chapters in Science
View all
1 Laws of Motion
2 Optics
3 Thermal Physics
4 Electricity
5 Acoustics
7 Atoms and Molecules
8 Periodic Classification of Elements
9 Solutions
10 Types of Chemical Reactions
11 Carbon and Its Compounds
12 Plant Anatomy and Plant Physiology
13 Structural Organisation of Animals
14 Transportation in Plants and Circulation in Animals
15 Nervous System
16 Plant and Animal Hormones
17 Reproduction in Plants and Animals
18 Genetics
19 Origin and Evolution of Life
20 Breeding and Biotechnology
21 Health and Diseases
22 Environmental Management
23 Visual Communication