TN Online TestSamacheer Kalvi · 1–12

Inverse Trigonometric Functions — Formula Sheet

Inverse Trigonometric Functions — Formula Sheet

1. Domains and principal-value ranges

2. Complementary identities

\[\sin^{-1}x+\cos^{-1}x=\frac{\pi}{2},\qquad \tan^{-1}x+\cot^{-1}x=\frac{\pi}{2},\qquad \sec^{-1}x+\operatorname{cosec}^{-1}x=\frac{\pi}{2}.\]

3. Reciprocal identities

\[\operatorname{cosec}^{-1}x=\sin^{-1}\frac{1}{x},\qquad \sec^{-1}x=\cos^{-1}\frac{1}{x},\qquad \cot^{-1}x=\tan^{-1}\frac{1}{x}\ \ (x\gt 0).\]

4. Negative-argument identities

\[\sin^{-1}(-x)=-\sin^{-1}x,\qquad \tan^{-1}(-x)=-\tan^{-1}x,\qquad \operatorname{cosec}^{-1}(-x)=-\operatorname{cosec}^{-1}x,\]

\[\cos^{-1}(-x)=\pi-\cos^{-1}x,\qquad \sec^{-1}(-x)=\pi-\sec^{-1}x,\qquad \cot^{-1}(-x)=\pi-\cot^{-1}x.\]

5. Cancellation laws

\[\sin(\sin^{-1}x)=x\ \ (|x|\le 1),\qquad \sin^{-1}(\sin\theta)=\theta\ \ \left(\theta\in\left[-\tfrac{\pi}{2},\tfrac{\pi}{2}\right]\right),\]

with the analogous statements for the other five functions, each restricted to its own principal range.

6. Conversions among inverses (for \(x\gt 0\))

\[\sin^{-1}x=\cos^{-1}\sqrt{1-x^{2}}=\tan^{-1}\frac{x}{\sqrt{1-x^{2}}}=\operatorname{cosec}^{-1}\frac{1}{x},\]

\[\cos^{-1}x=\sin^{-1}\sqrt{1-x^{2}}=\tan^{-1}\frac{\sqrt{1-x^{2}}}{x}.\]

7. Sum and difference of arctangents

\[\tan^{-1}x+\tan^{-1}y=\tan^{-1}\frac{x+y}{1-xy}\ \ (xy\lt 1),\qquad \tan^{-1}x-\tan^{-1}y=\tan^{-1}\frac{x-y}{1+xy}\ \ (xy\gt -1).\]

8. Sum of arcsines and arccosines (sufficient conditions shown)

\[\sin^{-1}x+\sin^{-1}y=\sin^{-1}\!\left(x\sqrt{1-y^{2}}+y\sqrt{1-x^{2}}\right),\quad x,y\ge 0,\ x^{2}+y^{2}\le 1,\]

\[\cos^{-1}x+\cos^{-1}y=\cos^{-1}\!\left(xy-\sqrt{1-x^{2}}\,\sqrt{1-y^{2}}\right),\quad x+y\ge 0.\]

9. Double- and triple-angle forms

\[2\tan^{-1}x=\sin^{-1}\frac{2x}{1+x^{2}}=\cos^{-1}\frac{1-x^{2}}{1+x^{2}}=\tan^{-1}\frac{2x}{1-x^{2}}\quad(\text{valid for suitable }x,\ \text{e.g. }|x|\le 1),\]

\[2\sin^{-1}x=\sin^{-1}\!\left(2x\sqrt{1-x^{2}}\right),\qquad 3\sin^{-1}x=\sin^{-1}(3x-4x^{3}),\qquad 3\cos^{-1}x=\cos^{-1}(4x^{3}-3x).\]

10. Handy boundary values

\[\sin^{-1}0=0,\ \ \sin^{-1}1=\frac{\pi}{2},\ \ \cos^{-1}1=0,\ \ \cos^{-1}0=\frac{\pi}{2},\ \ \tan^{-1}0=0,\ \ \tan^{-1}1=\frac{\pi}{4},\ \ \cot^{-1}1=\frac{\pi}{4}.\]

Solved MCQs → Practice test →

More for this chapter

Solved MCQsAnswers + explanations
Practice TestInteractive · instant score
Study NotesConcepts & methods
Book Back AnswersQuick answer key